uva--1339 - Ancient Cipher(模拟水体系列)

时间:2022-05-05
本文章向大家介绍uva--1339 - Ancient Cipher(模拟水体系列),主要内容包括1339 - Ancient Cipher、Input、Output、Sample Input、Sample Output、基本概念、基础应用、原理机制和需要注意的事项等,并结合实例形式分析了其使用技巧,希望通过本文能帮助到大家理解应用这部分内容。

                                                   1339 - Ancient Cipher

Ancient Roman empire had a strong government system with various departments, including a secret service department. Important documents were sent between provinces and the capital in encrypted form to prevent eavesdropping. The most popular ciphers in those times were so called substitution cipher and permutation cipher. Substitution cipher changes all occurrences of each letter to some other letter. Substitutes for all letters must be different. For some letters substitute letter may coincide with the original letter. For example, applying substitution cipher that changes all letters from `A' to `Y' to the next ones in the alphabet, and changes `Z' to `A', to the message ``VICTORIOUS'' one gets the message ``WJDUPSJPVT''. Permutation cipher applies some permutation to the letters of the message. For example, applying the permutation (2, 1, 5, 4, 3, 7, 6, 10, 9, 8)to the message ``VICTORIOUS'' one gets the message ``IVOTCIRSUO''. It was quickly noticed that being applied separately, both substitution cipher and permutation cipher were rather weak. But when being combined, they were strong enough for those times. Thus, the most important messages were first encrypted using substitution cipher, and then the result was encrypted using permutation cipher. Encrypting the message ``VICTORIOUS'' with the combination of the ciphers described above one gets the message ``JWPUDJSTVP''. Archeologists have recently found the message engraved on a stone plate. At the first glance it seemed completely meaningless, so it was suggested that the message was encrypted with some substitution and permutation ciphers. They have conjectured the possible text of the original message that was encrypted, and now they want to check their conjecture. They need a computer program to do it, so you have to write one.

Input 

Input file contains several test cases. Each of them consists of two lines. The first line contains the message engraved on the plate. Before encrypting, all spaces and punctuation marks were removed, so the encrypted message contains only capital letters of the English alphabet. The second line contains the original message that is conjectured to be encrypted in the message on the first line. It also contains only capital letters of the English alphabet. The lengths of both lines of the input file are equal and do not exceed 100.

Output 

For each test case, print one output line. Output `YES' if the message on the first line of the input file could be the result of encrypting the message on the second line, or `NO' in the other case.

Sample Input 

JWPUDJSTVP
VICTORIOUS
MAMA
ROME
HAHA
HEHE
AAA
AAA
NEERCISTHEBEST
SECRETMESSAGES

Sample Output 

YES
NO
YES
YES
NO

题意: 给你两个串a,b 需要你将a的每一类字母进行变换问能否得到b串
很简单的一个题目:
HAHA
HEHE  以这个为列子; 两种类型的字母,只需要比较a,b将所有类型的字母所形成的的数据一样,即他们能够有一样的个数需要一样,但是字母不需要相同

代码:
 1 //#define LOCAL
 2 #include<cstdio>
 3 #include<cmath>
 4 #include<cstring>
 5 char a[102],b[102];
 6 int c[26],d[26],e[102];
 7 
 8 int main()
 9 {
10   int i;
11   #ifdef LOCAL
12   freopen("test.in","r",stdin);
13   #endif
14   while(scanf("%s%s",a,b)!=EOF){
15    memset(c,0,sizeof(c));
16    memset(d,0,sizeof(d));
17    memset(e,0,sizeof(e));
18    for(i=0;a[i]!='';i++){
19          c[a[i]-'A']++;
20          d[b[i]-'A']++;
21    }
22     for(i=0;i<26;i++)
23     {
24       e[c[i]]++;
25       e[d[i]]--;
26     }
27     for(i=0;i<=100;i++)
28      if(e[i])break;
29     puts(i>100?"YES":"NO");
30   }
31   return 0;
32 }