Appium+python自动化29-toast消息

前言

appium1.5以后的版本才支持toast定位，并且 'automationName'得设置为'Uiautomator2'，才能捕获到。

一、 Supported Platforms

1.查看appium v1.7版本[官方文档](https://github.com/appium/appium/)

**Supported Platforms**
Appium supports app automation across a variety of platforms, like iOS, Android, and Windows. Each platform is supported by one or more "drivers", which know how to automate that particular platform. Choose a driver below for specific information about how that driver works and how to set it up:
- iOS
 - The [XCUITest Driver]
 - (DEPRECATED) The [UIAutomation Driver]
- Android
 - (BETA) The [Espresso Driver]
 - The [UiAutomator2 Driver]
 - (DEPRECATED) The [UiAutomator Driver]
 - (DEPRECATED) The [Selendroid Driver]
- The [Windows Driver](for Windows Desktop apps)
- The [Mac Driver] (for Mac Desktop apps)

2.从上面的信息可以看出目前1.7的android版可以支持：Espresso、UiAutomator2、UiAutomator、Selendroid四种驱动模式，后面两个不推荐用了，太老了，Espresso这个是最新支持的处于beta阶段，UiAutomator2是目前最稳的。

3.appium最新版本还能支持windows和mac的桌面app程序了，这个是否稳定，拭目以待！

二、 toast定位

1.先看下toast长什么样，如下图，像这种弹出来的消息"再按一次退出",这种就是toast了。

2.想定位toast元素，这里一定要注意automationName的参数必须是Uiautomator2才能定位到。

> 'automationName': 'Uiautomator2'
```
# coding:utf-8
from appium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from time import sleep
desired_caps = {
               'platformName': 'Android',
               'deviceName': '127.0.0.1:62001',
               'platformVersion': '4.4.2',
               'appPackage': 'com.baidu.yuedu',
               'appActivity': 'com.baidu.yuedu.splash.SplashActivity',
               'noReset': 'true',
               'automationName': 'Uiautomator2'
               }
driver = webdriver.Remote('http://127.0.0.1:4723/wd/hub', desired_caps)
# 等主页面activity出现
driver.wait_activity(".base.ui.MainActivity", 10)
driver.back()   # 点返回
# 定位toast元素
toast_loc = ("xpath", ".//*[contains(@text,'再按一次退出')]")
t = WebDriverWait(driver, 10, 0.1).until(EC.presence_of_element_located(toast_loc))
print t
```

3.打印出来的结果，出现如下信息，说明定位到toast了

><appium.webdriver.webelement.webelement session="02813cce-9aaf-4754-a532-07ef7aebeb88" element="339f72c4-d2e0-4d98-8db0-69be741a3d1b"></appium.webdriver.webelement.webelement>

三、封装toast判断

1.单独写一个函数来封装判断是否存在toast消息，存在返回True,不存在返回False

```
def is_toast_exist(driver,text,timeout=30,poll_frequency=0.5):
   '''is toast exist, return True or False
   :Agrs:
    - driver - 传driver
    - text   - 页面上看到的文本内容
    - timeout - 最大超时时间，默认30s
    - poll_frequency  - 间隔查询时间，默认0.5s查询一次
   :Usage:
    is_toast_exist(driver, "看到的内容")
   '''
   try:
       toast_loc = ("xpath", ".//*[contains(@text,'%s')]"%text)
       WebDriverWait(driver, timeout, poll_frequency).until(EC.presence_of_element_located(toast_loc))
       return True
   except:
       return False
```

四、参考代码

```
# coding:utf-8
from appium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
desired_caps = {
               'platformName': 'Android',
               'deviceName': '127.0.0.1:62001',
               'platformVersion': '4.4.2',
               'appPackage': 'com.baidu.yuedu',
               'appActivity': 'com.baidu.yuedu.splash.SplashActivity',
               'noReset': 'true',
               'automationName': 'Uiautomator2'
               }
def is_toast_exist(driver,text,timeout=30,poll_frequency=0.5):
   '''is toast exist, return True or False
   :Agrs:
    - driver - 传driver
    - text   - 页面上看到的文本内容
    - timeout - 最大超时时间，默认30s
    - poll_frequency  - 间隔查询时间，默认0.5s查询一次
   :Usage:
    is_toast_exist(driver, "看到的内容")
   '''
   try:
       toast_loc = ("xpath", ".//*[contains(@text,'%s')]"%text)
       WebDriverWait(driver, timeout, poll_frequency).until(EC.presence_of_element_located(toast_loc))
       return True
   except:
       return False
if __name__ == "__main__":
   driver = webdriver.Remote('http://127.0.0.1:4723/wd/hub', desired_caps)
   # 等主页面activity出现
   driver.wait_activity(".base.ui.MainActivity", 10)
   driver.back()   # 点返回
   # 判断是否存在toast-'再按一次退出'
   print is_toast_exist(driver, "再按一次退出")
```