java:利用xpath删除xml中的空节点

原始xml内容：

 1 <data>
 2   <a> </a>
 3   <b>b1</b>
 4   <awb>
 5     <awbpre>123</awbpre>
 6     <awbno></awbno>
 7   </awb>
 8   <spls>
 9     <spl />
10   </spls>
11 </data>

可用下面的代码去掉 <awbno></awbno>、<spls><spl/></spls>这二个空节点 （注<a> </a>中间有一个空格，不算空节点）

 1     @Test
 2     public void testDeleteEmptyNode() throws DocumentException {
 3         String xmlOrigin = "<data><a> </a><b>b1</b><awb><awbpre>123</awbpre><awbno></awbno></awb><spls><spl/></spls></data>";
 4         SAXReader saxReader = new SAXReader();
 5         Document document = saxReader.read(new ByteArrayInputStream(xmlOrigin
 6                 .getBytes()));
 7 
 8         while (true) {
 9             @SuppressWarnings("unchecked")
10             List<Element> list = document.selectNodes("//*[not(node())]");
11             if (list == null || list.size() <= 0) {
12                 break;
13             }
14             for (Element e : list) {
15                 System.out.println(e.getName());
16                 e.getParent().remove(e);
17             }
18         }
19         System.out.println(document.asXML());
20 
21     }

以上代码使用了dom4j

输出内容：

awbno spl spls <?xml version="1.0" encoding="UTF-8"?> <data><a> </a><b>b1</b><awb><awbpre>123</awbpre></awb></data>

即：

1 <data>
2   <a> </a>
3   <b>b1</b>
4   <awb>
5     <awbpre>123</awbpre>
6   </awb>
7 </data>