LeetCode SQL
时间:2022-07-25
本文章向大家介绍LeetCode SQL,主要内容包括其使用实例、应用技巧、基本知识点总结和需要注意事项,具有一定的参考价值,需要的朋友可以参考一下。
175.【简单】组合两个表
select p.FirstName,p.LastName,a.City,a.State from person p left join address a on p.personid=a.personid;
176.【简单】第二高的薪水
select ifnull((select distinct(Salary) from Employee order by Salary desc limit 1,1),null) as SecondHighestSalary;
177.【中等】第N高的薪水
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
set n=n-1;
RETURN (
# Write your MySQL query statement below.
select distinct Salary as getNthHighestSalary
from Employee
order by Salary DESC
limit N,1
);
END
181.【简单】超过经理收入的员工
select e1.Name as Employee from Employee as e1,Employee as e2
where e1.Salary > e2.Salary and e1.ManagerId = e2.Id;
182.【简单】查找重复的电子邮箱
select Email from Person
group by Email having count(Email)>1;
183.【简单】从不订购的客户
select c.Name as Customers from Customers c
left join Orders o on c.Id=o.CustomerId
where o.Id is null;
196.【简单】删除重复的电子邮箱
delete p1 from Person p1,Person p2
where p1.Email=p2.Email
and p1.Id > p2.Id;
197.【简单】上升的温度
select w1.Id from Weather w1,Weather w2
where DATEDIFF(w1.RecordDate,w2.RecordDate)=1
and w2.Temperature<w1.Temperature;
595.【简单】大的国家
select name,population,area from World
where area>3000000 or population>25000000;
596.【简单】超过5名学生的课
select class from courses
group by class
having count(distinct student)>=5;
620.【简单】有趣的电影
select * from cinema
where description <> "boring" and id%2=1
order by rating desc;
627.【简单】交换工资
update salary set sex = if(sex="m" ,"f", "m")
1179.【简单】重新格式化部门表
SELECT DISTINCT id AS "id",
SUM(IF (month = "Jan", revenue, null)) AS "Jan_Revenue",
SUM(IF (month = "Feb", revenue, null)) AS "Feb_Revenue",
SUM(IF (month = "Mar", revenue, null)) AS "Mar_Revenue",
SUM(IF (month = "Apr", revenue, null)) AS "Apr_Revenue",
SUM(IF (month = "May", revenue, null)) AS "May_Revenue",
SUM(IF (month = "Jun", revenue, null)) AS "Jun_Revenue",
SUM(IF (month = "Jul", revenue, null)) AS "Jul_Revenue",
SUM(IF (month = "Aug", revenue, null)) AS "Aug_Revenue",
SUM(IF (month = "Sep", revenue, null)) AS "Sep_Revenue",
SUM(IF (month = "Oct", revenue, null)) AS "Oct_Revenue",
SUM(IF (month = "Nov", revenue, null)) AS "Nov_Revenue",
SUM(IF (month = "Dec", revenue, null)) AS "Dec_Revenue"
FROM Department GROUP BY id
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