牛客寒假算法基础集训营5 I. 炫酷镜子(模拟)

时间:2022-06-18
本文章向大家介绍牛客寒假算法基础集训营5 I. 炫酷镜子(模拟),主要内容包括其使用实例、应用技巧、基本知识点总结和需要注意事项,具有一定的参考价值,需要的朋友可以参考一下。

题目链接:https://ac.nowcoder.com/acm/contest/331/I

       按找题意模拟就好了...代码略丑,不想改了...


AC代码:

#include <bits/stdc++.h>
using namespace std;
string str[505];
int n,m,pos;
bool flag;
 
void dfs(int x,int y,int h){
  while(1){
    if(x == -1 || y == -1 || x == n || y == m){
      if(x == n) flag = true, pos = y + 1;
      break;
    }
    // cout<<x<<"  "<<y<<endl;
    while(x >= 0 && y >= 0 && x < n && y < m && str[x][y] != '.'){
      // cout<<x<<"  "<<y<<endl;
      if(str[x][y] == '/'){
        if(h == 0){ y = y - 1, h = 2; continue;}
        if(h == 1){ y = y + 1, h = 3; continue;}
        if(h == 2){ x = x + 1, h = 0; continue;}
        if(h == 3){ x = x - 1, h = 1; continue;}
        // continue;
      }
      if(str[x][y] == '\'){
        if(h == 0){ y = y + 1; h = 3; continue;}
        if(h == 1){ y = y - 1; h = 2; continue;}
        if(h == 2){ x = x - 1; h = 1; continue;}
        if(h == 3){ x = x + 1; h = 0; continue;}
      }
      // cout<<x<<"  "<<y<<endl;
    }
    // cout<<x<<"  "<<y<<endl;
    if(x >= 0 && y >= 0 && x < n && y < m && str[x][y] == '.'){
      if(h == 0)x = x + 1;
      if(h == 1)x = x - 1;
      if(h == 2)y = y - 1;
      if(h == 3)y = y + 1;
    }
  }
}
 
int main()
{
  scanf("%d%d",&n,&m);
  for(int i=0;i<n;i++){
    cin>>str[i];
  }
  for(int i=0;i<m;i++){
    flag = false;
    dfs(0,i,0);
    if(flag == true)cout<<pos<<endl;
    else puts("-1");
  }
  return 0;
}