Joda-Time几个用法小记

1, 获取每天的零点

DateTime dt=new DateTime().withMillisOfDay(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));//结果2016-09-09 00:00:00

2, 在每天的6:30处理一些东西

DateTime dt=new DateTime().withHourOfDay(6).withMinuteOfHour(30).withSecondOfMinute(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));//结果2016-09-09 06:30:00

3, 在每月的7号的6:30处理一些东西

DateTime dt=new DateTime().withDayOfMonth(7).withHourOfDay(6).withMinuteOfHour(30).withSecondOfMinute(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));//结果2016-09-07 06:30:00

4, 在每年的8月的7号的6:30处理一些东西

DateTime dt=new DateTime().withMonthOfYear(8).withDayOfMonth(7).withHourOfDay(6).withMinuteOfHour(30).withSecondOfMinute(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));//结果2016-08-07 06:30:00

5, 获取每个月的第一天和最后一天

DateTime dateTime=new DateTime();
System.out.println(dateTime.dayOfMonth().withMinimumValue().dayOfMonth().get());
System.out.println(dateTime.dayOfMonth().withMaximumValue().dayOfMonth().get());//结果130

6, 获取每天的零点的下一天零点

DateTime dt=new DateTime().withMillisOfDay(0).plusDays(1);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));

7, 获取日期差

DateTime start=new DateTime(2015,5,4,12,20);
        DateTime start=new DateTime(2015,5,4,12,20);
        DateTime end=new DateTime(2015,5,6,3,10);
        Period period=new Period(start,end);
        System.out.println("month："+period.getMonths());
        System.out.println("days："+period.getDays());
        System.out.println("hours："+period.getHours());
        System.out.println("minutes："+period.getMinutes());
        System.out.println("second："+period.getSeconds());//结果month：0days：1hours：14minutes：50second：0

8, 单独获取天，小时，分钟，秒

DateTime start=new DateTime(2015,5,4,12,20);
        DateTime end  =new DateTime(2015,5,5,12,00);
        System.out.println(Days.daysBetween(start,end).getDays());
        System.out.println(Hours.hoursBetween(start,end).getHours());
        System.out.println(Minutes.minutesBetween(start,end).getMinutes());
        System.out.println(Seconds.secondsBetween(start,end));

9, 时间判断是否在某个范围以及获取时间差的毫秒

DateTime start=new DateTime(2015,5,4,12,20);
        DateTime end  =new DateTime(2015,5,5,12,00);
        Interval interval=new Interval(start,end);
        System.out.println(interval.contains(new DateTime(2015,5,5,11,00)));

        Duration duration=new Duration(start,end);
        System.out.println(duration.getStandardHours());

官网连接

http://www.joda.org/joda-time/userguide.html