CodeForces 663A Rebus - 码农教程

A. Rebus

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given a rebus of form ? + ? - ? + ? = n, consisting of only question marks, separated by arithmetic operation '+' and '-', equality and positive integer n. The goal is to replace each question mark with some positive integer from 1 to n, such that equality holds.

Input

The only line of the input contains a rebus. It's guaranteed that it contains no more than 100 question marks, integer n is positive and doesn't exceed 1 000 000, all letters and integers are separated by spaces, arithmetic operations are located only between question marks.

Output

The first line of the output should contain "Possible" (without quotes) if rebus has a solution and "Impossible" (without quotes) otherwise.

If the answer exists, the second line should contain any valid rebus with question marks replaced by integers from 1 to n. Follow the format given in the samples.

Examples

input

? + ? - ? + ? + ? = 42

output

Possible
9 + 13 - 39 + 28 + 31 = 42

input

? - ? = 1

output

Impossible

input

? = 1000000

output

Possible
1000000 = 1000000

#include <iostream>
#include <string.h>
#include <stdlib.h>
#include <algorithm>
#include <math.h>
#include <stdio.h>

using namespace std;
char a[1000];
int n;
int num1,num2;
int b[1000];
int main()
{
    gets(a);
    int len=strlen(a);
    num1=0;num2=0;
    int cnt=1;int pos;int now=1;b[0]=1;
    for(int i=0;i<len;i++)
    {
        if(a[i]=='+') {b[cnt++]=1;now++;}
        if(a[i]=='-') {b[cnt++]=-1;now--;}
        if(a[i]=='=')
        {
            pos=i;
            break;
        }
    }
    n=0;
    for(int i=pos+1;i<len;i++)
    {
        if(a[i]<='9'&&a[i]>='0')
            n=n*10+a[i]-'0';
    }
    for(int i=0;i<cnt;i++)
    {
        while(now<n&&b[i]<n&&b[i]>0)
            now++,b[i]++;
        while(now>n&&b[i]>-n&&b[i]<0)
            now--,b[i]--;
    }
    if(now!=n)
    {
        printf("Impossiblen");
        return 0;
    }
    printf("Possiblen");
    int j=0;
    for(int i=0;i<len;i++)
    {
        if(a[i]!='?')
        printf("%c",a[i]);
        else
        {
            printf("%d",abs(b[j++]));
        }
    }
    cout<<endl;
    return 0;
}