使用StrictRedis连接操作有序集合

看崔大佬的书，它连接redis使用的是StrictRedis，但是有序集合的操作zadd(name,*args,**kwargs)会报错，查看资料发现应该是zadd(name,iteritems)。

redis数据库中有序集合的操作

1，添加

from redis import StrictRedis

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
#向键grade的添加元素Bob分数为98
redis.zadd('grade',{'Bob':98,'Mike':80})

2，删除

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
#删键grade的元素Mike
redis.zrem('grade','Mike')

3，存在执行，不存在添加

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
#如果grade中存在Bob的元素则分数进行-2操作，否则添加
redis.zincrby('grade',-2,'Bob')

4，获取元素的排名

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
#获取grade中元素的排名
amy = redis.zrank('grade','吴志斌')
print(amy)

5，获取倒序

from redis import StrictRedis

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
#获取grade中元素的倒序排名
amy = redis.zrevrank('grade','吴志斌')
print(amy)

6，获取范围的元素

from redis import StrictRedis

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
#获取grade中排名列表
amy = redis.zrevrange('grade',0,3)
print(amy)

7，获取分数范围内的元素

from redis import StrictRedis

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
#获取80-100分数范围的元素
grade = redis.zrangebyscore('grade',80,100)
print(grade)

8，返回分数范围的元素个数

from redis import StrictRedis

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
#返回80-100分数范围的元素个数
grade = redis.zcount('grade',80,100)
print(grade)

9，获取键中元素的个数

from redis import StrictRedis

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
#获取键grade表中的元素个数
grade = redis.zcard('grade')
print(grade)

10，按排名删除元素

from redis import StrictRedis

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
#获取键grade表中排名1-3的元素
grade = redis.zremrangebyrank('grade',0,2)
print(grade)
返回删除元素的个数

11，删除分数范围的元素

from redis import StrictRedis

redis = StrictRedis(host='localhost',port=6379,db=0,password='foobared')
# 删除键grade中分数范围100-140的元素
redis.zremrangebyscore('grade',100,140)
返回的是删除元素的个数

12，

原文地址：https://www.cnblogs.com/wuzhibinsuib/p/12662412.html