结对项目（唐崇珂——谭艺）

int main()
{　　//检测是否存在这两个文件，如果没有就新建
    FILE *fp;
    fp = fopen("Exercises.txt", "w+");
    fclose(fp);
    fp = fopen("Answers.txt", "w+");
    fclose(fp);
    int range = 0;

    printf("请输入产生几以内的数字：");
    scanf_s("%d", &range);
    printf("\n请输入产生多少个运算表达式：");
    scanf_s("%d", &num);


    int right1 = 0;
    int wrong1 = 0;
    char(*result)[LENGTH] = (char(*)[LENGTH])malloc(sizeof(char)*LENGTH*num);
    int i;
    for (i = 1; i <= num; i++) {//随机生成四个数字
        //char expArr[2];//定义生成的题目
        int a = (int)(random(range));//分子
        int b = (int)(random(range));//分母
        int c = (int)(random(range));//另一个分子
        int d = (int)(random(range));//另一个分母
        int fuhao;//运算符
        fuhao = (int)(random(4));
        product_exp(a, b, c, d, fuhao, i, *result + i);//进入处理函数
    }
    free(result);
    printf("\n回答完成请按回车");
    getchar();
    getchar();
    check1();
    system("pause");
    return 0;
}

void myitoa(int num_i, char *str)
{
    int j = 0, i = 0;
    char number[10] = { '0','1','2','3','4','5','6','7','8','9' };
    char temp[10] = { 0 };
    while (num_i != 0)
    {
        temp[i] = number[num_i % 10];
        i++;
        num_i = num_i / 10;
    }
    temp[i] = '\0';
    i = i - 1;
    while (i >= 0)
    {
        str[j] = temp[i];
        j++;
        i--;
    }
    str[j] = '\0';
    //printf("%s", str);
}

int random(int a) {//随机数
    int b;
    b = rand() % a + 1;
    return b;
}

void product_exp(int a, int b, int c, int d, int fuhao, int y, char *result)
{
    int fenzi;
    int fenmu;
    char*ab = biaodashi(a, b);
    char*cd = biaodashi(c, d);
    FILE *fp;
    FILE *fp1;
    fp = fopen("Exercises.txt", "a");
    fp1 = fopen("Answers.txt", "a");
    if (b != 0 && d != 0)
    {
        switch (fuhao)
        {
        case 1:
            fenzi = a * d + b * c;
            fenmu = b * d;
            fprintf(fp, "%d:%s + ", y, biaodashi(a, b));
            fprintf(fp, "%s = \n", biaodashi(c, d));
            fprintf(fp1, "%d:%s\n", y, yuefen(fenzi, fenmu));
            break;
        case 2:
            if (a*d - b * c >= 0)
            {
                fenzi = a * d - b * c;
                fenmu = b * d;
                fprintf(fp, "%d:%s - ", y, biaodashi(a, b));
                fprintf(fp, "%s = \n", biaodashi(c, d));
                fprintf(fp1, "%d:%s\n", y, yuefen(fenzi, fenmu));
            }
            else
            {
                fenzi = b * c - a * d;
                fenmu = b * d;
                fprintf(fp, "%d:%s - ", y, biaodashi(c, d));
                fprintf(fp, "%s = \n", biaodashi(a, b));
                fprintf(fp1, "%d:%s\n", y, yuefen(fenzi, fenmu));
            }
            break;
        case 3:
            fenzi = a * c;
            fenmu = b * d;
            fprintf(fp, "%d:%s × ", y, biaodashi(a, b));
            fprintf(fp, "%s = \n", biaodashi(c, d));
            fprintf(fp1, "%d:%s\n", y, yuefen(fenzi, fenmu));
            break;
        case 4:
            if (c != 0)
            {
                fenzi = a * d;
                fenmu = b * c;
                fprintf(fp, "%d:%s ÷ ", y, biaodashi(a, b));
                fprintf(fp, "%s = \n", biaodashi(c, d));
                fprintf(fp1, "%d:%s\n", y, yuefen(fenzi, fenmu));
                break;
            }
            else
                break;


        default:
            break;
        }
        fclose(fp);
        fclose(fp1);
    }
}

char* yuefen(int a, int b)
{
    static char str[10] = { 0 };
    for (int k = 0; k < 10; k++)  //for循环初始化
    {
        str[k] = 0;
    }
    int y = 1;
    char c_z[LENGTH] = { 0 };
    for (int i = a; i >= 1; i--)
    {
        if (a%i == 0 && b%i == 0)
        {
            y = i;
            break;
        }
    }
    int z = a / y;
    int m = b / y;
    if (a == 0)
    {
        str[0] = '0';
        return str;
    }
    if (m == 1)
    {
        myitoa(z, c_z);
        strcat(str, c_z);
        return str;
    }
    else
        return biaodashi(z, m);
}

char* biaodashi(int a, int b)
{
    static char str[LENGTH] = { 0 };
    for (int k = 0; k < LENGTH; k++)  //for循环初始化
    {
        str[k] = 0;
    }
    char c_a[LENGTH] = { 0 };
    char c_c[LENGTH] = { 0 };
    char c_b[LENGTH] = { 0 };
    char c_d[LENGTH] = { 0 };
    myitoa(a, c_a);          //int转为char
    myitoa(b, c_b);
    if (a >= b)
    {
        int c;
        c = a / b;
        int d;
        d = a % b;

        myitoa(c, c_c);
        myitoa(d, c_d);

        {
            if (d == 0)
            {
                strcat(str, c_c);
                return str;
            }
            strcat(str, c_c);
            strcat(str, "\'");
            strcat(str, c_d);
            strcat(str, "\/");
            strcat(str, c_b);
            return str;
        }
    }
    strcat(str, c_a);
    strcat(str, "\/");
    strcat(str, c_b);
    return str;

}

int check1() {
    FILE *fp0;
    fp0 = fopen("Grade.txt", "w+");
    FILE *fp;
    FILE *fp1;
    int i = 0, j = 0, t = 0, w = 0, r = 0, l = 0, h = 0;
    int * rightcount = (int*)malloc((num + 2) * sizeof(int));
    memset(rightcount, -1, sizeof(rightcount));
    int * wrongcount = (int*)malloc((num + 2) * sizeof(int));
    memset(wrongcount, -1, sizeof(wrongcount));
    char StrLine[10] = {};             //每个答案最大读取的字符数
    char StrLine1[10] = {};
    if ((fp = fopen("Exercises.txt", "r")) == NULL) //判断文件是否存在及可读
    {
        printf("Exercises.txt error!");
        return -1;
    }
    if ((fp1 = fopen("Answers.txt", "r")) == NULL) //判断文件是否存在及可读
    {
        printf("Answers.txt error!");
        return -1;
    }

    char ch_Q = 0;
    char ch_A = 0;

    for (t = 1; t <= num; t++) {//一行
        ch_Q = fgetc(fp);
        if (ch_Q != EOF) {
            while (ch_Q != '\n') {//题目            
                if (ch_Q == '=') {
                    ch_Q = fgetc(fp);
                    for (i = 0; ch_Q != '\n'; i++) {
                        ch_Q = fgetc(fp);
                        StrLine[i] = ch_Q;
                    }
                    StrLine[i] = '\0';

                    ch_A = fgetc(fp1);
                    if (ch_A != EOF)
                        while (ch_A != '\n') {
                            if (ch_A == ':') {//答案
                                for (j = 0; ch_A != '\n'; j++) {
                                    ch_A = fgetc(fp1);
                                    StrLine1[j] = ch_A;
                                }
                                StrLine1[j] = '\0';
                            }
                            else
                                ch_A = fgetc(fp1);
                        }
                }
                else
                    ch_Q = fgetc(fp);
            }
        }
        for (int a = 0; StrLine1[a] != '\n'; a++) {
            if (StrLine[a] != StrLine1[a]) {
                w++;
                wrongcount[l] = t;//记录错的题号
                l++;
                wrongcount[l] = '\0';
                break;
            }
            else {
                if (StrLine[a + 1] == '\n' && StrLine1[a + 1] == '\n') {
                    r++;
                    rightcount[h] = t;  //记录对的题号
                    h++;
                    rightcount[h] = '\0';
                    break;
                }
            }
        }


    }
    fprintf(fp0, "Correct: %d (", r);
    for (int g = 0; rightcount[g] != '\0'; g++)
        fprintf(fp0, "%d ", rightcount[g]);
    fprintf(fp0, ")\n");

    fprintf(fp0, "Wrong: %d (", w);
    for (int g = 0; wrongcount[g] != '\0'; g++)
        fprintf(fp0, "%d ", wrongcount[g]);
    fprintf(fp0, ")\n");

    fclose(fp0);
    fclose(fp);
    fclose(fp1);                     //关闭文件
    free(rightcount);
    free(wrongcount);

    return 0;
}