使用$.post方式来实现页面的局部刷新功能

时间:2019-09-16
本文章向大家介绍使用$.post方式来实现页面的局部刷新功能,主要包括使用$.post方式来实现页面的局部刷新功能使用实例、应用技巧、基本知识点总结和需要注意事项,具有一定的参考价值,需要的朋友可以参考一下。
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
<script src="js/jquery-3.3.1.min.js"></script>
<script>
function fun() {
$.post("ajaxServlet",{username:"light",age:15},function (data) {
alert(data);
},"text");
}

</script>
</head>
<body>
<input type="button" value="发送异步请求" onclick="fun();">
<input type="text">
</body>
</html>

package cn.hopetesting.com;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;

/**
* @author newcityman
* @date 2019/9/16 - 21:53
*/
@WebServlet("/ajaxServlet")
public class AjaxServlet extends HttpServlet {
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String username = request.getParameter("username");
/* try {
Thread.sleep(5000);
} catch (InterruptedException e) {
e.printStackTrace();
}*/
System.out.println(username);
response.getWriter().write("hello,"+username+".");
}

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
this.doPost(request, response);
}
}
 

原文地址:https://www.cnblogs.com/newcityboy/p/11530977.html