1、Java8 增强工具类：Arrays

1.1、二分查找key元素值在数组a的索引，数组a的类型为基本数据类型，且数组已经按升序排序。

public static int binarySearch(long[] a, long key) {
        return binarySearch0(a, 0, a.length, key);
    }


   private static int binarySearch0(long[] a, int fromIndex, int toIndex,
                                     long key) {
        int low = fromIndex;
        int high = toIndex - 1;

        while (low <= high) {
            int mid = (low + high) >>> 1;
            long midVal = a[mid];

            if (midVal < key)
                low = mid + 1;
            else if (midVal > key)
                high = mid - 1;
            else
                return mid; // key found
        }
        return -(low + 1);  // key not found.
    }

带范围的二分查找，与上面类似。

    public static int binarySearch(long[] a, int fromIndex, int toIndex,
                                   long key) {
        rangeCheck(a.length, fromIndex, toIndex);
        return binarySearch0(a, fromIndex, toIndex, key);
    }

将原来的数组复制一个新的数组，长度为length，length小于原数组的长度则截取，大于原数组的长度则补0。

    public static <T> T[] copyOf(T[] original, int newLength) {
        return (T[]) copyOf(original, newLength, original.getClass());
    }

    public static <T> T[] copyOfRange(T[] original, int from, int to) {
        return copyOfRange(original, from, to, (Class<? extends T[]>) original.getClass());
    }

比较两个数组是否相同

    public static boolean equals(long[] a, long[] a2) {
        if (a==a2)
            return true;
        if (a==null || a2==null)
            return false;

        int length = a.length;
        if (a2.length != length)
            return false;

        for (int i=0; i<length; i++)
            if (a[i] != a2[i])
                return false;

        return true;
    }

将数组赋值

    public static void fill(long[] a, long val) {
        for (int i = 0, len = a.length; i < len; i++)
            a[i] = val;
    }

    public static void fill(long[] a, int fromIndex, int toIndex, long val) {
        rangeCheck(a.length, fromIndex, toIndex);
        for (int i = fromIndex; i < toIndex; i++)
            a[i] = val;
    }

将数组排序，核心快速排序DualPivotQuicksort.sort，O(n log(n)) performance

    public static void sort(int[] a) {
        DualPivotQuicksort.sort(a, 0, a.length - 1, null, 0, 0);
    }

    public static void sort(int[] a, int fromIndex, int toIndex) {
        rangeCheck(a.length, fromIndex, toIndex);
        DualPivotQuicksort.sort(a, fromIndex, toIndex - 1, null, 0, 0);
    }

将数组转换成一个字符串

    public static String toString(long[] a) {
        if (a == null)
            return "null";
        int iMax = a.length - 1;
        if (iMax == -1)
            return "[]";

        StringBuilder b = new StringBuilder();
        b.append('[');
        for (int i = 0; ; i++) {
            b.append(a[i]);
            if (i == iMax)
                return b.append(']').toString();
            b.append(", ");
        }
    }

将数组并发排序

    public static void parallelSort(long[] a) {
        int n = a.length, p, g;
        if (n <= MIN_ARRAY_SORT_GRAN ||
            (p = ForkJoinPool.getCommonPoolParallelism()) == 1)
            DualPivotQuicksort.sort(a, 0, n - 1, null, 0, 0);
        else
            new ArraysParallelSortHelpers.FJLong.Sorter
                (null, a, new long[n], 0, n, 0,
                 ((g = n / (p << 2)) <= MIN_ARRAY_SORT_GRAN) ?
                 MIN_ARRAY_SORT_GRAN : g).invoke();
    }